(x^2-2x)^2-3x^2+6x-4=0

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Solution for (x^2-2x)^2-3x^2+6x-4=0 equation: 



(x^2-2x)^2-3x^2+6x-4=0

We add all the numbers together, and all the variables

-3x^2+6x+(x^2-2x)^2-4=0

We move all terms containing x to the left, all other terms to the right

-3x^2+6x+(x^2-2x)^2=4

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